squared digit length

**peter_hii** · 03-31-2006

hi everyone this is my code for square digit length

Code:

#include <iostream>
using namespace std;

int main()
{
    int day = 29;
    int mod;
    int div;
    int total;
    int counter = 0;
    int working = ((mod * mod) + (div * div))
    
    mod = day%10;//gives 9
    div = day/10;// gives 2
    total = day;
    
    while(working != 4 || working != 1)
    {
        total = (mod * mod) + (div * div);
        
        counter++;
    }    
    cout<<counter<<endl;
    
    
    
system("pause");
return 0;
}

is not working, can someone help me on this?

and i got a problem for changing the integer for day ..

**Sebastiani** · 03-31-2006

>> int working = ((mod * mod) + (div * div))

at this point mod and div are uninitialized.

>> while(working != 4 || working != 1)

your loop makes no sense. working never gets modified so the loop becomes infinite. besides that, the assignment in the loop will always yield the same result.

**DeepFyre** · 03-31-2006

just as you said

Code:

int counter = 0;

you have to say

Code:

int mod = 0;//or whatever value

likewise

Code:

int div = 0;//or whatever value

Code:

    while(working != 4 || working != 1)
    {
        total = (mod * mod) + (div * div);
        
        counter++;
    }

lets think about this....ASSUMING that div = 0 (which it doesnt) and assuming that mod = 0 (which it doesnt) ... working = (0 * 0) + (0 * 0)
working = 0

now ... after you set working = ((mod * mod) + (div * div)) ... does that value ever change after that?

**skorman00** · 03-31-2006

To add to (maybe clarify) Salem's comment: the condition for the while loop will never be false.

**peter_hii** · 04-01-2006

can someone give me some idea on how to count the squared digit length.

for example 29 is input

and the process should be like this:

2^2 + 9^2 = 85
8^2 + 5^2 = 89
8^2 + 9^2 = 145
1^2 + 4^2 + 5^2 = 42
4^2 + 2^2 = 20
2^2 + 0^2 = 4

this loop ends when the final solution ==4 or 1, and count how many step it takes....

can someone please give me some idea... ? please?

**Salem** · 04-01-2006

Code:

#include <stdio.h>

int calc ( int value ) {
  int result = 0;
  while ( value > 0 ) {
    int digit = value % 10;
    result = result + digit * digit;
    value = value / 10;
  }
  return result;
}
int main ( ) {
  int num = 29;
  while ( num > 10 ) {
    int result = calc ( num );
    printf( "%d -> %d\n", num, result );
    num = result;
  }
  return 0;
}


$ gcc bar.c
$ ./a.out
29 -> 85
85 -> 89
89 -> 145
145 -> 42
42 -> 20
20 -> 4

**peter_hii** · 04-01-2006

wow man.... thnx for giving full... hehe figure out myself...thnx ...

**peter_hii** · 04-01-2006

but how to cout the number of step ?

**peter_hii** · 04-01-2006

is alright, i got it ...

**peter_hii** · 04-01-2006

can someone explain on this part of code

Code:

        result = result + digit * digit;
        day = day / 10;

**Salem** · 04-01-2006

Why don't you put a printf() inside the loop of that function and print each one out?

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