Thread: Functions help

i wanted to see if i could get a simple function setup, something called from within in main nothing to hard...

Well it worked eventually, at least i think it did and the funciton was called. So i wanted to see if i could add another, however after adding it, it compiled but nothing happens. The original function isn't called anymore, even though i would have thought by looking at it that it would call the first one (sequence),a dnt hen the next one (alldone) after input into the first function is done.

any ideas on what simple fundemental thing i've done wrong
it's not like i've spent several hours on it already

Code:

# include <iostream>
# include <stdio.h>

using namespace std;

int Seqeunce(void)

{
      
      int Sequence ;
      
    cout << "Input Residue Sequence: "<< endl;
    cin >> Sequence;
    cin.ignore();
    
     cout << "Sequence entered: "<< Sequence <<"\n";
     
     
   return 0;
  
}
int Alldone(void)

{
    char done;
    
    cout <<"All Done!"<< endl;
    cin >> done;
    cout << "Done: "<< done <<"\n";
    return 0;
}



int main (int argc, char* argv[]) 
{


{
    Seqeunce();
}

{    
    Alldone();    
}    


cin.get();
 }

You dont use these "{" in main, just:

Code:

int main(){
 //all code here
}

edit: I have tested your code and it works here.

The extra parentheses shouldn't cause any problems. The code work for me. What input do you give?

Thank you all, i don't even thin i want to mention the embaressment when i found out it wasn't running because even though i clcked compile and run in dev c++ it decided to run a seperete exe file.

I'am now going to scratch my eyes out while i contemplate how i got myself into this situation

apologises for all who got it to work first time. i didn't mean to waste your time sorry.

regards Wolfe

>> your main() function should "return 0" or you will get warning.

Only on older, non-standard compilers. You are allowed to leave out the return 0 in the main function.