Thread: Quick Question

method 1: convert to string, then use/convert individual chars as needed
method 2: mod by 10 to get last digit, then divide by 10 to remove last digit, repeat till you get to 0

with method two you are getting the numbers in reverse order so I'd suggest you use a deque and push_front() to automagically arrange them

>I have a question. I want to break up an integer by digits.
One way is to use the modulus (%) operator and division (/) operator in a loop:

Code:

//loop
   digit = num % 10;
   num = num / 10;
//end loop

Modulus and division, modulus by 10 gets the last digit. Divide by 10 to cut off the last digit:

Code:

std::list<int> List;

while(Number > 0)
{
  List.push_front(Number % 10);
  Number /= 10;
}

This will add all digits to the list.