plz,need some help

**davtan** · 02-23-2006

hey,i need help here....i need codes on how to auto generate id ...

Code:

#include <iostream>
#include <string>
#include <fstream>
#include "staffDetails.h"

using namespace std;


void staffDetails::getStaffInfo()
{
    char yes;
	
	
		cout<<"Please enter staff's name:";
		cin>>name>>endl;
		cout<<"Please enter staff's address:";
		cin>>address>>endl;
		cout<<"Please enter staff's ID number:";
		cin>>SID>>endl;
	
		cout<<"Please enter staff's c number:";
		cin>>c_no>>endl;

	save();

}

void staffDetails::save()
{
		fstream instaff;
	instaff.open("staff.dat",ios::in|ios::app);
	if(instaff.fail())
	{
		cerr<<"File opening error!";
		exit(-1);
	}

	  instaff>>name>>address>>SID>>c_no;
	instaff.close();
}
>

**Ideswa** · 02-23-2006

staff member id = number_of_staff_members + 1

something like that?

**SlyMaelstrom** · 02-23-2006

What do you want the ID to look like? All numbers, a mix of letters and numbers? Do you do want their realname to be involved somehow (ie contains their initials)?

Look into <ctime> and the rand() function, that should put you on the right track.

**Ideswa** · 02-23-2006

http://cboard.cprogramming.com/showthread.php?t=76088

some random generating topic.

**davtan** · 02-23-2006

yea..maybe a mix of characters and numbers would be good
for example,
id=csd001

i should use a for loop rite?

**SlyMaelstrom** · 02-23-2006

With the letters you're going to have to use rand() to get their ascii values then convert them to characters. Go to http://www.lookuptables.com they have an ascii chart. If you don't want it random, consider that the letters could be the employees initials.

**davtan** · 02-23-2006

what if i want the id to be in numbers only?

**SlyMaelstrom** · 02-23-2006

Again, what numbers do you want? Random numbers? If so then use the rand() function. If you want it based on other data, such as the number of employees you have then you can use that.

**Ideswa** · 02-23-2006

numbers 0-9 = ascii 48-57

so use:

Code:

int blaat = rand() % (57 - 48) +48;

**SlyMaelstrom** · 02-23-2006

No, no. You don't need ascii values for numbers. Because rand returns an integer.

Code:

#include <cstdlib>
#include <ctime>
/* cstdlib for srand() and rand() and ctime to seed srand() */
using namespace std;

int main() {
   srand(time(NULL));

   int randomNum = rand() % 9 + 1;   // A random number between 1 and 9.
   
   return 0;
}

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plz,need some help

thanx

hey