Thread: help to reverse this function

Ok I have a function

Code:

int stylecodes(char *input, char *out, int max) {
	int c = 0;
	char *str = input;
	memset(out,'\0',max);
	unsigned int i = 0;
	for (i = 0; i < strlen(input); ) {
		if (strncmp(str,"%c%",3)==0) {
			snprintf(out,max,"%s%c",out,3);
			str+=3;
			c++; i+=3;
		} else if (strncmp(str,"%b%",3)==0) {
			snprintf(out,max,"%s%c",out,2);
			str+=3;
			c++;i+=3;
		} else if (strncmp(str,"%o%",3)==0) {
			snprintf(out,max,"%s%c",out,15);
			str+=3;
			c++;i+=3;
		} else if (strncmp(str,"%u%",3)==0) {
			snprintf(out,max,"%s%c",out,31);
			str+=3;
			c++;i+=3;
		} else if (strncmp(str,"%i%",3)==0) {
			snprintf(out,max,"%s%c",out,22);
			str+=3;
			c++;i+=3;
		} else {
			snprintf(out,max,"%s%c",out,str[0]);
			str++;
			i++;
		}
	}
	return c;
}

now I want a fuction, which makes these steps backwards. Lets say the fuction replaces the string %c% with the ascii code 3 then I need a function which replaces the ascii code 3 back to
%c%

THX for everyone who can help me!

OK, so did you try to do it yourself already?

yeah I try to change ,"%c%" to "" . That works but the character 31 for %u% I cant type in my programm.
I need a command which converts a number to its ascii code. For example:

Code:

if (strncmp(str,chr(3),1)==0) {
	snprintf(out,max,"%s%s",out,"%c%");
	str+=1;
	c++; i+=1;

But c++ don't have a command like chr or I don't know it.

Now I try this

Code:

	const char *replace;
	snprintf(replace,sizeof(replace),"%c",3);
	for (i = 0; i < strlen(input); ) {
		if (strncmp(str,replace,1)==0) {

but

error C2664: '_snprintf' : cannot convert parameter 1 from 'const char *' to 'char *'

That's a big problem, because the function strncmp() want as second parameter a const char and I don't know how to give this function the ascii code 3. Please help me.

if you wanna replace a char containing a number as an ascii code, just do int x = y - '0'; (assuming y's a char)

> snprintf(replace,sizeof(replace),"%c",3);
Well replace doesn't point anywhere, and being a pointer, sizeof() doesn't do what you probably want it to do (assuming the pointer pointed somewhere)

> and I don't know how to give this function the ascii code 3.
Like

Code:

if ( strncmp ( buff, "%c\003", 3 ) == 0 )  // A character specified as 3 octal characters
if ( strncmp ( buff, "%c\x03", 3 ) == 0 )  // A character specified as 2 hex characters

> if (strncmp(str,"%c\x03",1
Well there are 3 chars in your string, not 1.

Originally Posted by Salem

> if (strncmp(str,"%c\x03",1
Well there are 3 chars in your string, not 1.

Hmm I understand it that way the %c\x03 represented the third ascii code. That is what I'm searching for in my string and this have a len of 1. When I write if (strncmp(str,"%c\x03",3
noting happens the char is as it was before.

I need something which finds the third ascii code. I looked that up in the msdn

http://msdn.microsoft.com/library/en...ml/vc38qo1.gif

and what I need is the ETX Code. I want to search for that in my text an replaces it with %c%

This is an example:

[7 %test% 3]

And the things before the "7" and the "3" I want to replace with %c%

"%c\x03"
%
c
\x03

Are 3 characters.

Perhaps you're matching entirely the wrong thing.

Originally Posted by Salem

"%c\x03"
%
c
\x03

Are 3 characters.

Perhaps you're matching entirely the wrong thing.

Ok I see it %c\x03 cant be ascii code 3, because this function replaces every % in my text with a %c%. That is not really what I want. I only want to replace:

ascii3 with %c%
ascii2 with %b%
ascii15 with %o%
ascii31 with %u%
ascii22 with %i%

Perfect Dave_Sinkula works exactly the way I want this function work. Thx alot