Thread: trun string input into if output

Code:

if(say == "HI"||"Hi"||"hi"||"Hello"||"hello"||"HOLA"||"Hola"||"hola")

"Hola"||"hola" etc is always true. Compare say with each individually.

So I should show them individually?

Code:

else if(say = bla bla)

He means like this:

Code:

if(say == "Hi" || say == "Hola")

Just the word "Hola" is as good as saying not zero... which is true.

you may want to look into creating something to capitalize your input to help you out...

Code:

#include <iostream>
#include <cstring>

char*capitalize(char*in);	//warning: this changes the input string

int main()
{
	char*buffer=new char[1024];

	std::cout<<"Enter a word: ";
	std::cin.getline(buffer,1024,'\n');
	
	if(!strcmp(capitalize(buffer),"HELLO"))
	{
		std::cout<<"Why Hello There";
	}
	else
	{
		std::cout<<"No Hello first?";
	}
	
	std::cout<<std::endl;
	delete[]buffer;
	return 0;
}

char*capitalize(char*in)
{
	short int len=strlen(in);
	for(register short int i=0;i<len;i++)
	{
		in[i]=toupper(in[i]);
	}
	return in;
}

This is using char*'s, but it'd be a quick easy change to convert it to stl strings.

toupper() is in <cctype>, not <cstring>.

And adr, getchar() is a C function, in <cstdio>. I don't know if you've included this or not since you didn't post tt.h.

[edit]

Code:

short int len=strlen(in);

And strlen() returns a size_t. I think size_t is typedefed in <cstdio> or <cstddef>.
[/edit]

well, strlen is from <cstring>, and if it returns a type, that type must have been defined, so therefore if you've included strlen(), you must have indirectly included size_t as well

Yes, but the fact remains that you tried to stuff a size_t into a short int.