Thread: Why does this loop keep going?

I have the following code:

Code:

#include <iostream>

using namespace std;

void get_int(int& number);

int main()
{
int n;

get_int(n);
cout << "Final value read in = " << n << endl
<< "end of demo.\n";
return 0;
}


void get_int(int& number)
{
char ans;
do
{
cout << "Enter input number:";
cin >> number;
cout << "You entered " << number
<<" Is that correct? (yes/no): ";
cin >> ans;
} while ((ans != 'Y') && (ans != 'y'));
}

If I enter a number, say 8, and then enter some random letters such as "gjh" the loop keeps going with out prompting me for more input. I can see why it would loop, but why does it not prompt me to enter another number?

What compiler are you using ? When I compile it in Visual C++ 2005 Express, it works just fine.

>> if I enter a number, say 8, and then enter some random letters such as "gjh" the loop keeps going with out prompting me for more input. I can see why it would loop, but why does it not prompt me to enter another number?

If you enter more then one character then they stay in the buffer. The leftover characters will be used for the next input of number.
Kurt