Thread: Arhg, stupid syntax error, am I misusing make_pair?

The code

Code:

template < typename resource_t >
void Manager<resource_t>::Add_To_List(const std::string & Filename, resource_t *)
{
	Resources.insert( std::make_pair( Filename , resource_t *) );
}

And the error

Code:

--------------------Configuration: Resource_Manager - Win32 Debug--------------------
Compiling...
Resource_Manager.cpp
C:\Documents and Settings\colemanjon\Desktop\Resource_Manager 1\Resource_Manager.cpp(70) : error C2059: syntax error : ')'
        c:\program files\microsoft visual studio\vc98\include\xmemory(59) : while compiling class-template member function 'void __thiscall Manager<class MS3DModel>::Add_To_List(const class std::basic_string<char,struct std::char_traits<char>,class 
std::allocator<char> > &,class MS3DModel *)'
Error executing cl.exe.
Creating browse info file...

Resource_Manager.exe - 1 error(s), 0 warning(s)

This is like, the last function that is causing my resource_system to be incomplete, please help!

>void Manager<resource_t>::Add_To_List(const std::string & Filename, resource_t *)
You didn't give "resource_t *" a variable name. Then change make_pair to use this name.

so setup a variable or struct or whatever that can be set equal to make_pair,

then pass that?

Let me add the function declaration just in case that is the problem..

Code:

	void Add_To_List( const std::string & Filename, resource_t* );

No look closely:
>void Manager<resource_t>::Add_To_List(const std::string & Filename, resource_t *)

>resource_t *
See this. You have a type definition, but where's the name of the variable? For example:

Code:

void Manager<resource_t>::Add_To_List(const std::string & Filename, resource_t *Resource)

Thanks alot, that was it.. Silly me

I figured its type would just be whatever I templated in the declaration of the manager

Manager<MS3DModel> Models;

I thought it would automatically take the form of an MS3DModel...