Overloaded operator[] question

[dee.dw]

I have a simple question but could find the answer in a thread...

I have a myString class and overloaded the operator[] with

char& operator[](unsigned int index);
const char& operator[](unsigned int index) const;

(Actually it's the same as in the vector class: http://www.cppreference.com/cppvecto...operators.html)

In my main Routine I have the following:

myString test("hello");
test[0]='c';
printf("%c\n", test[0]);

My question is, why in both cases only the first overloaded function is called... Is there a way to separate assignment and return-value?

Greetings, Dee

[dwks]

printf is C. My guess is that it takes a char, not a const char. Try writing your own function:

void function(const char c) {
    cout << c;  // or printf
}

Can you even do that?

[dwks]

Wait, I have it. Use a const object and see if the second operator[] is called.

[dee.dw]

Thanks for your answer... Yes, that was my problem. I misinterpreted the way opf the second function! It will work when I use a const object...

Greetings, Dee