Thread: please,helpe me in correcting this code!!

Hi everybody ,
I know very little about this high language,
for my studying field in BA is far & different
from the PC programming languages,which I’m studying
it to take a diploma in it. So , kindly I want your help.
I really spent two days in searching the e-books and
other forum to find a way or a rule, but I failed.
I wrote this broken code ,broken, because many of it’s
statements are not completed .Please help me, and who
wants to help me in solving them has to read these four
items carefully;
1- My program run on Microsoft Visual C++ 6.0.
2- I wrote my questions between the explanation
marks(/* */),to specify the place of my questions.
3- My program must include only
the <iostrem.h> library; why?,because this what I only
did study, in this quarter.
4- I must use the( do/while , for )as loop
statements and (switch/case), (if/else if)as conditional
and selective statements).
5- I left the condition blank as in while( ) empty .

Code:

#include <iostream.h>
void main()
{ 
int PartNo,Required_Qauntity ;
   // here is a two dimensional array 
int x[3][3]={10,50,100,20,60,200,30,70,300};
cout<<"PartNo\ tQuantityNo\tPartPrice\n";
for(int i=0;i<3;i++)
{ cout<<"\n";
for(int j=0;j<3;j++)
cout<<x[i][j]<<"\t";
}
do
{
cout<<"\nEnter the part number:\n\n ";
 cin>> PartNo; 
/* the program must search this PartNo in the array,.and 
if it is found , 
 it must go to the 3rd (do/while)statement, to ask the user 
to "Enter the Required_Qauntity",
 but if it isn't found the program must go to the first 
statement.."enter PartNo",How??*/
  do
  {
 for ()
 {
// how can I complete this condition (if it's correct!!)
   if(PartNo = = 
  {
//if the PartNo is exist then		  
 cout<<"this PartNo is exist, and it's:\n"<<  ( display the 
entered PartNo)<<"\n";
 break;}
}
	 
/* if the PartNo not found then print the next output & go 
to the first statement.." Enter the PartNo" */
cout<<" PartNo is not  exisit\n";

 }while (  );

 do
 { cout<<"\n";
 cout<<"Enter the Required_Qauntity:\n";
cin>>Required_Qauntity;
/*the program must search the array to find if this RQ is
 exist or no,If yes ,thenit must display it. If  No,it prints 
"This Qauntity is not available" and 
 goes back to the the first  statement .." Enter the PartNo".*/
cout<<"The Required_Qauntity is not avaliable";
}while(  );
/* what is the condition here in the basic (do/while)*/
}while(  );
}

thank you

Thanks Mr.The Brain, I really appreciate your help, I benefited from your code, but displaying an element from the array mustn’t be with bool ,it must be by using loop as (do/while) and select statements, could you give keywords help me in solving it by one of these ways, just clues.
I formatted my program but it doesn’t do the following mathematical statement.
Quantity * Price = …
How can I correct this rule( x[++index][2] ) to give me the specific element from the array? x[++index][2]
“The price of the sold quantity is $"<<" "<<Required_Quantity<<"*"<<x[++index][2] <<"="<<Required_Quantity*x[++index][2]<<"\n";

This is the code:

Code:

#include<iostream.h>



int main()
{

     int PartNo,Price;
		 int Required_Quantity;
		 int Quantity; 
	 int answer;
	  
     // here is a two dimensional array 
     int x[3][3]={10,50,100,20,60,200, 30,70,300};

     
     cout<<"PartNo\t  Quantity      Price\n";
     
     for(int i=0;i<3;i++)
     {
          cout << endl;                
          for(int j=0; j<3; j++)         
               cout<<x[i][j]<<" ";
     }

	
     e: cout<<"\n\nEnter the part number:\n ";
         
		cin>> PartNo; 
          

          int index;  
          bool found = false;              
          for (index=0; index<3 && !found; index++)
    
              if(PartNo == x[index][0])
        
                  found = true;        

          if(found)
         
		  {
	  
               cout<<"\nthis PartNo is exist, and it's"<<" "<< x[--index][0] <<"\n";              
               cout<<"\nEnter the Required_Qauntity: ";
               cin>>Required_Quantity;
              
			  	
				  if(Required_Quantity > x[index][1] || Required_Quantity <=0)	 
			  
			
				  {cout<<"\nThe Required_Quantity is not available";
		 
			 goto e;
				  }


		   else	
			   
         
		  
                 cout<<"\nThe Required_Quantity is available at "<<x[--index][1]<<"\n"; 
		  
			     
              
		  
		  
		  
		  do
		  {
               
		  cout<<"\nDo you want to continue the selling process?Please choose the answer.\n";
		  cout<<"1- YES.\n";

          cout<<"2- NO.\n";
		   cin>>answer;

		  switch (answer)
		  {
		  case 1:
			 
			  { if(answer=='y' || answer=='Y')

               
              cout<<"\n";
			  cout<<"The price of the sold qauntity is"<<" "
			<<Required_Quantity<<"*"<<x[++index][2] <<"="<<Required_Quantity*x[++index][2]<<"\n";
		      cout<<"the part number is "<<PartNo<<",the avaliable qauntity is"<<Quantity<<","<<
			"the remain qauntity is"<<Quantity<<"-"<<Required_Quantity<<"="<<Quantity-
			Required_Quantity<<"and the price of the sold qauntity is $"<<" "
			<<Required_Quantity<<"*"<<x[++index][2] <<"="<<Required_Quantity*x[++index][2]<<"\n";
			  }
			  
	    	case 2:
			if(answer=='n' || answer=='N')
			
               goto e;
			  
			
		  }
		
	    	do
			 {
            cout<<"\nDo you want to make another selling process?Please choose the answer.\n";
		  cout<<"1- YES.\n";

          cout<<"2- NO.\n";
		   cin>>answer;

		  switch (answer)
		  {
		  case 1:
			 
			  if(answer=='YES' || answer=='yes')
				  
				  cout<<"\tgo:\n";
			 goto e;

			  
			 case 2:
                 
				 
				
				break; 
				
		  }

		  }while(answer=='n');

		  }while(answer=='n');
		   }

	else
          {
            cout<<"\nPartNo is not  exisit\n";
			goto e ;
	}

	 
		  


}

And on that note - closed.