Thread: String Help!!!

Can you post the whole code or is it too long?

I don't about the error you are showing...you need to give the complete code for that...but there is another error in this code...it should be

Code:

(str.size()+1);

instead of

Code:

((str.size)+1);

Originally Posted by gtr_s15

yeah it is bit long

Let me save your time...follow these steps
1.Ctrl+A
2.Ctrl+C
3.Ctrl+V

Originally Posted by sunnypalsingh

I don't about the error you are showing...you need to give the complete code for that...but there is another error in this code...it should be

Code:

(str.size()+1);

instead of

Code:

((str.size)+1);

... and this error would likely make the compiler issue a statement like "invalid use of member", because it's... an invalid use of a member

But what would & have to do with anything?

Don't know what you exactly want, anyway this is the official syntax:
#include <string>
void resize( size_type num, const TYPE& val = TYPE() );

So, you cannot just add 1 in the resize syntax, as you did here:

str.resize((str.size)+1);

Instead, try something like this:

Code:

int newsize = str.size() + ;1
str.resize(newsize);

Here's an example:

Code:

#include <string.h>
#include <iostream.h>

using namespace std;

int main ()
{
	string some_string;
	int new_string_size;
	
	cout << "Enter a string:\n";
	cin >> some_string;
	cout << "string size = " << some_string.size () << endl << endl;
	
	if (some_string.size () % 2 == 0)
	{
		cout << "Your string size is even.\n";
	} else
	{
		new_string_size = some_string.size () + 1;
		some_string.resize (new_string_size);
		
		cout << "Your string size was odd and has now been made even.\n\n";
	}
}