Thread: Weird special character text after output

Code:

while (count < LINELENGTH)

My guess is the above is causing problems because the string you enter from the keyboard is probably not that long. You need to do something like this.

Code:

int len = strlen(phrase);
while( count < len )
{

Thanks for the help! It's not displaying that text anymore except for it is missing one word now...but that I can fix.

Also does anyone have any idea on how to account for \r, \n, \t...but when i make the while loop look for it...I get the error "illegal escape sequence"?

Thanks,

...Dan

'\n' is a single character, so just check for '\n' instead of '\' and 'n' separately. Also, remember to use == instead of = when checking for equality. You probably don't have to worry about '\r', it is converted automatically to '\n' by the stream code.

If it is a single character...when it is typed in with a string...lets say: hello\nworld

wouldn't the strlen count 12 characters...\n as 2?

...Dan

No, that's 11 characters. The \ is just an escape character to indicate that you are using a special character. There is no newline character on your keyboard, so you use an escape sequence to indicate that you want the newline to appear there.

Right now my code is looking like this:

Code:

#include <iostream>
using namespace std;

#define LINELENGTH 100

void spaceWords(char phrase[]);

int main(void)
{
	while (!cin.eof())
	{
		
		char phrase[LINELENGTH] = {' '};
		
		cout << "Please enter a line of text: ";
		cin.getline (phrase, LINELENGTH);

		spaceWords(phrase);
	}
	return 0;
}
void spaceWords(char phrase[])
{
	int count = 0;
	int total = 0;
	int base = 0;
	int count2 = 1;
	int length = strlen(phrase);

	//loop until count is equal to line length
	while (count <= length)
	{
		//while not a blank space, add to the counter
		while (phrase[count] != ' ')
		{
			count ++;
		}

		//print out word number	
		cout << "Word " << count2 << ": ";

		for (base; (base <= count) && (count <= length); base ++)
		{
			cout << phrase[base];
		}
		cout << '\n';
		count++;
		base = count;
		count2 = count2 + 1;		
	}
}

The problem is that since I got rid of the extra characters added in using the line strlen...now my last word is not being displayed...I have tried many things to get it to display but it wont. The really weird thing is if I type in Hello World...the count before the hello will reach 5 (which is correct...5 characters) but after it loops, before World will reach 192 (which is obviously not correct). If i use more than two words, it is always the last world that has an unusually high count number

Any help would be great,

...Dan

You need to check for count less than length in the loop looking for the space. Remember that there is no space at the end of "Hello World". There aren't any characters. The second time through your loop looking for the space will go on forever until it finds a space in the unknown memory that you access past the bounds of phrase. Simply break that loop if you reach the end of phrase and it should work better.

Thanks Daved! The program is working great now.

Thanks you guys for the help,

...Dan

I have one last problem and then it should be good. I am having trouble with finding \n in the input and then separating the words. I came up with this line but it did not work:

Code:

while ((phrase[count] != ' ') && (count < length) && (phrase[count] != '\n'))

Thanks again for the help,

...Dan

There won't be any newline in the input. You use getline to get the data. The getline function reads up until the first newline, but doesn't include that newline in the text it saves in the string (it just ignores it). So phrase will never have a newline character in it as long as you use getline to read in the line.

When count is no longer less than length, then you know you've reached the end of the line.

Well this is what the teacher asked us to do:

Write a complete C++ program that will read a line of text at a time from the keyboard as a string. Your program will separate it into words for any of these 4 whitespace characters -- blank ' '; tab '\t'; return '\r'; and newline '\n' – and print each word. Upon receiving end of file, your program will terminate.
Use cin.getline() to read a whole line of input at a time (see both table 6-3 on page 218 and table 6-4 on page 219) as in this sample code fragment:

#define LINELEN 100
...
char buffer[LINELEN];
...
cin.getline(buffer, LINELEN);

No string functions are required, but you may use them if you wish. However, you may not use the function strtok() if you should happen across it. It is deprecated since it alters its string argument without warning. You can compare characters with == in an if or while statement, or use a switch statement for one char.
Your screen will resemble:

Enter string: test one line now
Word 1: test
Word 2: one
Word 3: line
Word 4: now
Enter string: ^Z

I think where my program is at now it will account for what the teacher wants to input. If I like type in Hello <TAB KEY> WORLD, is displays both words correctly. Does it appear that I am missing anything?

Yes you do miss something. You are not checking for the tab-character.
If you input multiple whitspace characters you count them as a word.
Kurt