Thread: Overriding '+' operator

  1. #1
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    Overriding '+' operator

    Hello, everyone.

    I was wondering is it possible to override the addition operator so that it will take two constants of type char*.

    I tried writing the following code but it only gave me an error message stating "'operator +' must have at least one formal parameter of class type".

    Code:
    char* operator+(const char* left, const char* right)
    {
    	char* c, *d;
    	d = new char[strlen(left) + 1];
    	strcpy(d, left);
    	c = new char[strlen(left) + strlen(right) + 1];
    	c = strcat(d, right);
    	return c;
    }
    So, is it fundamentally impossible to override this operator outside a user defined class, or is there a way to do it?

    If so, how?

    Thanks.

  2. #2
    Frequently Quite Prolix dwks's Avatar
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    Why do you want to overload it with two const char *s? That already exists, and that's what the compiler's complaining about.
    dwk

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  3. #3
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    Oops, didn't explain enough in my post.

    I just wanted to try and create something like the string handlers you find in Visual Basic.

    In visual basic you can do this:
    Code:
    Dim S as String
    S = "Hello" + "World!"
    S = "Hello" & "World!"
    Either '+' or '&' would function as concatenation operators if they were passed strings.

    I know you can't do that with character pointers in c++. But can you override them to act like the Visual Basic concatenators if the operands were character pointer constants?

  4. #4
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    I was wondering is it possible to override the addition operator so that it will take two constants of type char*.
    No, that is why you are getting this error:
    I tried writing the following code but it only gave me an error message stating "'operator +' must have at least one formal parameter of class type
    You can only overload operators for members of a user defined class:
    http://geneura.ugr.es/~jmerelo/c++-f...html#faq-26.10
    Last edited by 7stud; 11-14-2005 at 04:21 PM.

  5. #5
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    Just use the C++ string class and its operator+
    Code:
    std::string S;
    S = "Hello" + std::string("World!");
    // or
    S = std::string("Hello") + "World!";
    // or the best option for small additions:
    S = "Hello";
    S += "World";

  6. #6
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    Thanks. Now I know better.

    If C++ let you redefine the meaning of operators on built-in types, you wouldn't ever know what 1 + 1 is: it would depend on which headers got included and whether one of those headers redefined addition to mean, for example, subtraction.

  7. #7
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    ...or
    Code:
    string char1 = "o";
    string char2 = "k";
    cout<<char1 + char2<<endl;

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