Thread: converting double to long int

I'm trying to convert a double to a long int, but i keep getting a warning message saying :

34 C:\Dev-Cpp\PROG1B.cpp [Warning] converting to `long int' from `double'

How do i ignore the warning so i can compile it?

Here's how i started setting up the code:

Code:

#include <iostream>
#include <math.h>
#include <cmath>

using namespace std;

int main()
{

//Declaring Variables

double tendered;
double purchase;
double chg;
long change;
int fives;
int ones;
int half;
int quarters;
int dimes;
int nickels;
int pennies;
    
    cout << "Enter purchase amount: ";
    cin >> purchase;
    
    cout << "Enter tendered amount: ";
    cin >> tendered;
    
    //Calculating change amount
    chg = tendered - purchase;
    
    //Converting double to long 
    change = ceil(chg * 100);
    
    
    //Display error message if change is more than 19.99
    
    If (chg > 19.99)
       cout << "Amount to return is: " << chg << "--Sorry just dont have that amount of change";
    getch();
    return 0;
    
    fives = change / 5;
    ones = (change - 5) / 1;
    
    cout << "Fives" << fives; 

return 0;
}

ok. I have an error that I think is the main problem:

38 C:\Dev-Cpp\PROG1B.cpp `If' undeclared (first use this function)
(Each undeclared identifier is reported only once for each function it appears in.)

I thought that i did the if statement correctly, but apparently not.

Code:

#include <iostream>
#include <cmath>

using namespace std;

int main()
{

//Declaring Variables

double tendered;
double purchase;
double chg;
long change;
int fives;
int ones;
int half;
int quarters;
int dimes;
int nickels;
int pennies;
    
    cout << "Enter purchase amount: ";
    cin >> purchase;
    
    cout << "Enter tendered amount: ";
    cin >> tendered;
    
    //Calculating change amount
    chg = tendered - purchase;
    
    //Converting double to long 
    change = ceil(chg * 100);
    
    
    //Display error message if change is more than 19.99
    
    If (change > 1999.00)
       cout << "Amount to return is: " ;
       cout << chg << " --Sorry, I dont have that amount of change" << endl;

    //change = ceil(chg*100);            
    
    fives = change / 500;
        
    cout << "Fives" << fives; 

return 0;
}

Originally Posted by hk_mp5kpdw

Remember C++ is a case-sensitive language. If and if are two completely different things.

oops....well the fixed everything. Thanks!