Thread: Making proper wrappers.

Hope this isn't a stupid question, but Im trying to make a proper wrapper for printf.

I get the proper output doing the following:

Code:

text.hprintf("test\n");

The output is:

Code:

test

But I get a wierd output if I do:

Code:

text.hprintf("test\n%i", 123456789);

The output is:

Code:

test
1244892

Here's the small source.

main.cpp

Code:

//Alot of these includes are not used.
//Most will be used in the future.
#include <cstdlib>
#include <fstream>
#include <iostream>
#include <fstream>
#include <windows.h>
#include <cstring>
#include <time.h>
#include "output.h"

CTextOutput text;

int main(){
	char omfg;
	int i = 0;
	while(1){
		if(i==0)
		text.hprintf("test\n%i", 123456789);
		std::cin>>omfg;
		i=1;
		}
	return 0;
}

output.h

Code:

#ifndef OUTPUT_H
#define OUTPUT_H

class CTextOutput
	{

	private:
	
	public:

	int hprintf(const char* string, ...);
	int haprintf(const char* string, ...);

	};

#endif

output.cpp

Code:

#include <cstdlib>
#include <iostream>
#include <fstream>
#include <windows.h>
#include <string>
#include <cstring>
#include <time.h>
#include "output.h"

int CTextOutput::hprintf(const char* string, ...)
{
printf(string);
return 0;
}
int CTextOutput::haprintf(const char* string, ...)
{
printf("<<: ");
printf(string);
return 0;
}

This was my attempt at a custom wrapper. Any ideas?

Originally Posted by bladerunner627

Any ideas?

http://www.eskimo.com/~scs/C-faq/q15.5.html