i need an array of pointers to functions that can be set to a variable size.
is it possible? or will i have to just set it to a constant size...Code:void (*functions[3])(void*,void*); //works, but not what i'm looking for void (*functions[vSize])(void*,void*); //doesnt work (expected constant expression) void (**functions)(void*,void*); //can't allocate later, because new constant won't work with void objects
Maybe like this?
Typdefs make function pointers easierCode:#include <iostream> typedef void (*pFunc)(void); void someFunc(pFunc* fcnArray, int size) { for (int i=0;i<size;i++) fcnArray[i](); } void Fcn1() { std::cout<<"Function 1!"<<std::endl; } void Fcn2() { std::cout<<"Function 2!"<<std::endl; } void Fcn3() { std::cout<<"Function 3!"<<std::endl; } int main() { pFunc myFcnArray[3]; myFcnArray[0] = Fcn1; myFcnArray[1] = Fcn2; myFcnArray[2] = Fcn3; someFunc(myFcnArray,3); }
And check out function-pointer.org
"Think not but that I know these things; or think
I know them not: not therefore am I short
Of knowing what I ought."
-John Milton, Paradise Regained (1671)
"Work hard and it might happen."
-XSquared
Code:#include <iostream> using namespace std; typedef void(*pfunc)(int); void func1(int num) { cout<<"func1: "<<num<<endl; } void func2(int num) { cout<<"func2: "<<num<<endl; } void func3(int num) { cout<<"func3: "<<num<<endl; } int main() { pfunc MyFunctions[3] = {func1, func2, func3}; int size = 0; cout<<"Input the array size: "; cin>>size; pfunc* funcArray = new pfunc[size]; for(int i=0; i<size; i++) { funcArray[i] = MyFunctions[i]; } for(int j=0; j<size; j++) { funcArray[j](j * 10); } delete [] funcArray; return 0; }
Last edited by 7stud; 10-18-2005 at 12:33 AM.
