Initializing char arrays on the free store

[roktsyntst]

OK. I have some code, but there has to be an easier way. I want to declare a char *-style string on the free store and initialize it at the same time. What I'd like to do, in other words, is something like this:

char * theString = "TEST STRING";

But with dynamic memory, like:

char * theString = new char("TEST STRING");

But that obviously does not work. Does anybody know what I'm talking about and can help me with it? Thanks!

[Eibro]

char *test = new char[strlen(someotherchar) + 1];
strcpy(test, someotherchar);
Remember to include string.h

[roktsyntst]

Thanks for the response....
Is there a similar solution for other types of arrays, e.g. int's?

[beege31337]

Originally posted by roktsyntst
Thanks for the response....
Is there a similar solution for other types of arrays, e.g. int's?

yeah, almost the same way

for example

int main(){

int *array;

int size;
cout << "How Big Do You want your array?";
cin >> size;

array = new int[size];

}

[roktsyntst]

Thanks, but I'm talking about initializing...

i.e. on the stack you can say:

int array[5] = { 1, 5, 9, 12, 13 }; // Initialize it with a set of numbers right away

But on the heap you have to say:

array = new int[5];

Is there some place to put the initializer list or do you have to go one by one and copy it from some other array? Thanks again!

[Hammer]

You have to copy them in. You may be able to do more than one at a time, depending on where they are coming from.

[Monster]

In C:

#include <stdio.h>
#include <string.h>

int main(void)
{
   char *msg = strdup("Hello world in C\n");
   if(msg) printf(msg);
   free(msg);
   return 0;
}

In C++:

#include <iostream>
#include <string>

int main(void)
{
   string msg = "Hello world in C++\n";
   std::cout << msg;
}