Splitting out large numbers

[omishompi]

So I ran into a problem the other day and need to separate out a large number into small number groups for example:

945689234989910

needs to be split into

9456|8923|498|9910

and each group needs to be stored

Anyone have any ideas?
Thanks in advance

[Thantos]

No code on your part means no code on my part.

However You could look into:
the string class
the substr method
and a simple for loop

[hk_mp5kpdw]

Read it as text then convert the strings into integer values as needed.

[omishompi]

Could it be more easily done with division and modulus?

[loko]

Yes substr method would be the easiest way to do it. Read input as text, then use substr method of string. then convert evry slice using atoi function(or is there a C++ version?).

[Enahs]

Could it be more easily done with division and modulus?

Yes, very easily.

#include <iostream>

using namespace std;
int main()
{

	int test;
	test = 12345;

	cout<< endl<< test%10 << " Last digit";
	cout<< endl<< test%100 << " Last two digits";
	cout<< endl<< test%1000 << " Last three digits" << endl;
	//ect

return 0;
}

[Thantos]

Yes, very easily.

Ok give me the middle the 3rd set of 3 digits in:
945689234989910
probably won't be as easy as: str.substr(6,3);

The biggest concern I have about trying to keep everything as integral types is that:
945689234989910 is a lot larger than a 32 bit int can handle. So if you are on a system with that limitation then using the int datatype isn't going to work.

[Enahs]

Bah, I did not even see the "more" part of what I quoted! Just showing it could be done.
It would not be very hard to pick the different parts out with that method; but your method is easier. I was just confirming with him that it could be done how he suggested.

[omishompi]

So Enahs how could you pick the different parts out?

Thanks everyone for all the help

[Thantos]

Using division / modulus is easist done when working from low values to high values:

int main()
{
  unsigned num = 123456789;
  int i = 1000; // We want to print them in sets of 3 digits
  while ( num > 0 )
  {
    cout << (num % i) << endl;
    num /= i;
  }
}

I'll leave it to you to figure out how to go from high to low (there are several methods)

[rogue]

You could use a double char **. Sigh, it's a thought

Rogue