Im making a tree type structure, it has 26 branches, each for a letter of the alphabet. i was wondering how can i make an array of pointers to a Node struct.
will this work?Code:template <class T> struct Nodes { ... }; typedef struct Nodes Node; template <class T> class Foo { Node *list[26]; public: ... };
Last edited by Mastadex; 09-30-2005 at 02:40 PM.
Node<T>* list[26];
Are you sure? some of the tutorials i read dont have the <T> there.
>> Are you sure?
No, but if you compile the code with the <T> and again without, one works and one doesn't. You have to specify the template type of Node somehow, which is why the <T> should be in there.
Code:template <class T> struct Node { }; template <class T> class Foo { Node *list[26]; public: }; int main() { Foo<int> ifoo; }Code:error C2955: 'Node' : use of class template requires template argument list
how is the compiler going to know what type to make Node if you don't tell it to? You definitely need to use Node<T> maybe the book had a typo, you will learn that there are a lot of errors in technical books, more than you would imagine.
