Thread: Taking inputs at Command Line

I have a problem. If my program is executed from the Command Prompt similar to:

C:\some_directory\program.exe input1 input2

How do I access the extra inputs? I've tried messing around with everything and the only output I can get is how many inputs are done.

Code:

int main (int argc){
cout << argc
}

with C:\ some_directory\program.exe input1 input2 input3

returns 3.

Thanks in advance.
Stephen.

Originally Posted by Stephenf

Code:

int main (int argc){
cout << argc
}

This is not a valid prototype for main.
It should be

Code:

int main (int argc, char ** argv){
   for ( int i = 0; i < argc; ++i )
      cout << argv[i] << endl;
   return 0;
}

Kurt