pointy pointy

[FoodDude]

I'm trying to understand passing a pointer to a function so the function modifies the stored value.

Example

rval = myfunction (rval)
	
std::string& rmyfunction(std::string& strText)
{
//stuff goes on
return strText;
}

BUT if I'm passing a pointer the fn, can't I write

myfunction (rval)
	
void myfunction(std::string& strText)
{
//stuff goes on
}

[Dae]

I'm trying to understand passing a pointer to a function so the function modifies the stored value.

Example

rval = myfunction (rval)
	
std::string& rmyfunction(std::string& strText)
{
//stuff goes on
return strText;
}

BUT if I'm passing a pointer the fn, can't I write

myfunction (rval)
	
void myfunction(std::string& strText)
{
//stuff goes on
}

Yes, because its a reference to the object you are actually modifying that object.

[FoodDude]

cool...thought I was loosing my mind.

[Ancient Dragon]

BTW: that isn't a "pointer" -- its a reference.

std::string& rmyfunction(std::string& strText) <<< referencde
{
}


std::string* rmyfunction(std::string* strText) <<< pointer
{
}