here's what i'm trying to do. I want to input a number into a variable, (int,float,double).. i want to display it's address, and display the bytes in big endian form.. (intel machines are little endian)
so, i can print the address, but &variable.. the problem is, i need the address to have spaces...
so for example, i can print "ox454567, but i want it to be 0x 45 45 67. to do this i need to go through memory byte by byte.
So, how can i go through memory byte by byte,, the code below is trying to do what i described..
but it's not working.. it keeps printing byte values inside the address
Code:void IntType(void) { int num0; char conti0; char *addr0; cout << endl; cout << endl; cout << "Enter an integer:"; cin >> num0; addr0 = (char*)(&num0); cout << endl; cout << endl; cout << "Address:0x"; cout << hex << addr0; cout << " Big endian representation:"; cout << endl; cout << endl; cout << endl; cout << endl; cout << endl; cout << endl; while(1) { cout << "press 'c' to continue:"; cin >> conti0; cout << endl; if(conti0 == 'c' || conti0 == 'C') break; } cout << endl; cout << endl; cout << endl; cout << endl; cout << endl; cout << endl; cout << endl; }