Thread: help with displaying memory addresses

here's what i'm trying to do. I want to input a number into a variable, (int,float,double).. i want to display it's address, and display the bytes in big endian form.. (intel machines are little endian)

so, i can print the address, but &variable.. the problem is, i need the address to have spaces...

so for example, i can print "ox454567, but i want it to be 0x 45 45 67. to do this i need to go through memory byte by byte.

So, how can i go through memory byte by byte,, the code below is trying to do what i described..
but it's not working.. it keeps printing byte values inside the address

Code:

void IntType(void)
{
	int num0;
	char conti0;
	char *addr0;
	

	cout << endl;
	cout << endl;
	cout << "Enter an integer:";
	cin >> num0;

	
	addr0 = (char*)(&num0);
	

	

	cout << endl;
	cout << endl;
	cout << "Address:0x";
	cout << hex << addr0;

	cout << "          Big endian representation:";
	cout << endl;
	cout << endl;
	cout << endl;
	cout << endl;
	cout << endl;
	cout << endl;

	while(1)
	{
		cout << "press 'c' to continue:";
		cin >> conti0;
		cout << endl;
		if(conti0 == 'c' || conti0 == 'C') break;
	}

	cout << endl;
	cout << endl;
	cout << endl;
	cout << endl;
	cout << endl;
	cout << endl;
	cout << endl;

}