Convert string to char[200]

[maxorator]

How can I convert a string to char[200]?

[Tonto]

Use the std::string c_str() member, to return a char*. More info:

http://www.msoe.edu/eecs/cese/resources/stl/string.htm
http://www.cppreference.com/cppstring/c_str.html

You should always check the reference pages.

[Dae]

Heres a post found about it using google, fourth on the list when searching: string to char c++
http://66.102.7.104/search?q=cache:n...+c%2B%2B&hl=en

The poster gives his version to convert it saying x line isnt working, then at the bottom of the page someone gives the solution line.

[Daved]

Why do you think you need to convert a string to char[200]? There's a good chance you don't.

[Rashakil Fol]

You you specifically want an array as in char x[200]; to be filled, you can use the std::copy subroutine provided by the <algorithm> header. E.g.

#include <algorithm>
#include <string>

int main() {
    std::string s("Hello!");
    char x[200];
    *(std::copy(s.begin(), s.end() - s.begin() < 200 ? s.end() : s.begin() + 199, x)) = 0;

}

This code makes sure that no more than 199 elements are copied, leaving room for the null terminator and assigning it. You should only use c_str() if you intend on only using the returned read-only char* before your next non-const member function on s -- so that makes it only good for short-term use, like functions or methods that expect char*s. You could use strncpy on the c_str, but that's no better than std::copy. In fact, it might be worse because at least one implementation of c_str() that I vaguely remember reading about copies the contents of the string into a separate buffer.