Thread: dynamic allocation.

  1. #1
    ... arjunajay's Avatar
    Join Date
    May 2005

    dynamic allocation.

    How do I declare multi dimensional arrays?

    char *ptr;
    ptr = new char[size];
    Worked... but...
    char **ptr;
    ptr = new char[3][2];
    Gives an error 'Cannot convert char[2]* to char **'.
    char * ptr[];
    ptr = new char [2][3];
    Obviuosly gave an error 'The size of ptr[] is unknown or zero.'

    I tried some other combinations in vain; but they gave errors like 'Lvalue required'.
    I checked many books, but they only give the syntax for single dimensional arrays...
    Please Excuse if this question looks really stupid or if the answer is obvious...

  2. #2
    and the hat of int overfl Salem's Avatar
    Join Date
    Aug 2001
    The edge of the known universe
    This only works if you know the sizes of your minor dimensions at compile time

    char (*ptr)[2];
    ptr = new char[3][2];
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.

  3. #3
    Skunkmeister Stoned_Coder's Avatar
    Join Date
    Aug 2001
    you do nopt make a 2d array dynamically like that in c++. There is no operator new[][].
    You will need to use a couple of loops. It has been covered many times. Search the boards to find code samples.
    Free the weed!! Class B to class C is not good enough!!
    And the FAQ is here :-

  4. #4
    ... arjunajay's Avatar
    Join Date
    May 2005
    Boy, now this's quick reply.
    I wanted to declare an array to store the data in a 'raw' file.
    since I don't know the the dimensions of the file forehand, I asked this question...

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