Thread: How come this works?

  1. #1
    Registered User
    Join Date
    Jan 2005

    How come this works?

    #include <iostream>
    #include <string>
    std::string Func()
    	std::string linha;
    	std::getline(std::cin, linha);
    	return linha;
    int main()
    	std::string linha;
    	linha = Func();
    	std::cout << linha << std::endl;
    In function Func(), I'm returning a local variable and the program displays the correct result. I can't figure out why...

  2. #2
    ATH0 quzah's Avatar
    Join Date
    Oct 2001
    I suspect the string class has a copy constructor which dupes the string. Much like returning an integer or what not returns a copy (value actually) when you return one.

    Hope is the first step on the road to disappointment.

  3. #3
    C++ Witch laserlight's Avatar
    Join Date
    Oct 2003
    Yeah, it looks normal - you arent returning a reference to the local string after all.
    Quote Originally Posted by Bjarne Stroustrup (2000-10-14)
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  4. #4
    Registered User mrafcho001's Avatar
    Join Date
    Jan 2005
    That code looks ok to me... i mean it is suppose to return a string...

  5. #5
    Carnivore ('-'v) Hunter2's Avatar
    Join Date
    May 2002
    It's the same situation as:
    int func1()
       return 1;  //Returning 1 by value
    std::string func2()
       return std::string("Some String");  //Return a copy of std::string("Some String")
    You're just returning a value. The problem is, as laserlight mentioned, when you try returning a reference or pointer:
    int& func1()
       int localVariable;
       return localVariable;  //localVariable won't exist after func1() ends
    std::string* func2()
       std::string localString("Some String");
       return &localString;  //This address will point to nothing when func2() ends
    Just Google It. √

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