In function Func(), I'm returning a local variable and the program displays the correct result. I can't figure out why...Code:#include <iostream> #include <string> std::string Func() { std::string linha; std::getline(std::cin, linha); return linha; } int main() { std::string linha; linha = Func(); std::cout << linha << std::endl; }
Thanks.
I suspect the string class has a copy constructor which dupes the string. Much like returning an integer or what not returns a copy (value actually) when you return one.
Quzah.
Hope is the first step on the road to disappointment.
Yeah, it looks normal - you arent returning a reference to the local string after all.
Look up a C++ Reference and learn How To Ask Questions The Smart WayOriginally Posted by Bjarne Stroustrup (2000-10-14)
That code looks ok to me... i mean it is suppose to return a string...
It's the same situation as:
You're just returning a value. The problem is, as laserlight mentioned, when you try returning a reference or pointer:Code:int func1() { return 1; //Returning 1 by value } std::string func2() { return std::string("Some String"); //Return a copy of std::string("Some String") }
Code:int& func1() { int localVariable; return localVariable; //localVariable won't exist after func1() ends } std::string* func2() { std::string localString("Some String"); return &localString; //This address will point to nothing when func2() ends }
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