Thread: Function Problems....

i get a bunch of errors with my mult func. being at the top and i forgot how to make functions properly how do i fix this?

Code:

#include <iostream>
#include <cstdlib>

using namespace std;
 
int a;
int b;
int c;

void voided() {
cout << "doesnt return anythin so im void" << endl;
}

void mult(a, b);

int main() 
{
    cout << "4 + 6 IS "<< mult(4, 6) <<"!" << endl;
    cout << "void function "<< voided <<"" << endl;
    system("PAUSE");
    return 0;
}
mult(a, b) {
a + b = c; //a plus the value of be assigns the answer to c
return c; // gives the answer ex if a is 2 and b is 3 it would return 5
}

>void mult(a, b);
If you want your function to return a value then declare it so:

Code:

int mult(int a, int b);

And your assignment statement is backwards.

?????

i tried to make it not bein void but says it must be declared nd that mult is not declared/defined

and i thought that was how u made a prototype function

lol no! i used to know em really well then i started API and forgot it lol

Eh... That last statement makes no sense at all.

Anyway, an example:

Code:

// Good...
int foo(int x);

int main { ... }

int foo(int x)
{
   return 1;
}

// Bad...
int foo(int x);

int main { ... }

int foo(/* nothing here */ x)
{
   return 1;
}

// Also bad...
int foo( );

int main { ... }

/* nothing here */ foo( )
{
   return 1;
}

The signature of the function for both declaration and definition must match exactly*. And, C++ is strongly typed; all variables must have a type.

* This excludes the parameter names (and only the names). So, the following are fine:

Code:

void foo(int x);
void foo(int fred)
{
   cout << fred; // **not** cout << x;
}

void bar(int);
void bar(int y)
{
   cout << y;
}

Cheers

i remembered while doin my classes lol ty all