Thread: Amature needs help please!

Originally Posted by JoshR

You'd have to change the if to...

if charCount is equal to a space or newline or tab or EOF

Oh yah tab, if charCount is equal to space or tab. Not EOF because the while statement ends when its at the EOF.

BTW, my school only has 2 computer classes, networking and communications, and computer study, both are just basic crap. No programming classes, the person who said they have c++/java class are lucky.

Originally Posted by dra

Not to be an ass or anything but although your code does a few interesting things, it doesn't achieve the topic creator's task which is to count words. althought you could count spaces, then add 1....

"One Two" <--- one space : 1 + 1 = 2 words. lol. But that's too much work in my opinion.

He must have editted his post, because he said that he was just giving the topic creator an idea of how to do it, how to count spaces and such will give the topic creator an idea of how to count words. Which is what your topic was like also, to give the topic creator an idea, not give him the complete program.

Originally Posted by dra

althought you could count spaces, then add 1....

"One Two" <--- one space : 1 + 1 = 2 words.

Counting spaces does not work.

How many words are in this file:

Code:

one         two          three

Originally Posted by JoshR

But...You have to know when the EOF has been found so you can count the last word

Ohhh yeah you're right you would if you were counting by spaces. In that case I'd use dra's code, count strings, thats the one I was thinking of cause I was playing with that code myself, it works well and easily.

Originally Posted by jaybo684

dae...how do you write the code if it counts the strings?

I dont know how I can help without giving you the program, its pretty much exactly what dra's code is:

Code:

#include <iostream>
#include <string>

using namespace std;

int main(){
    
    string s;
    int i = 0;
    while ( cin >> s ){
          
          i++;
    }
    
    cout << "You entered " << i << " words.";
}

Open the file, and instead of cin.. use the file. I dont know if using a string is more efficient than using a char and counting words based on spaces/tabs/n/and eof, but it works and the code is simple.

Originally Posted by Rashakil Fol

Counting spaces does not work.

How many words are in this file:

Code:

one         two          three

it was just a suggestion....

besides, assuming the sentences are properly written, as in one space between each word, and two after a sentence, he could probably get away with it.

But even then, it's too much work. Letting the library do all the work is best. lol.

I would just use a char array for 5.5

technically, you'd be reading it in character by character

With all the "hints" given on this topic and on that actual page, theres a hints link, you should be able to figure it out. Dra's code implimented with what I said to do is 5.4 (with the addition of "asking for the filename to be opened (stored in a string)"). In 5.5 you simply do the same thing but instead of taking a string at a time from the file, take a char (as it says to do), and test if its a space, tab, end of line, or end of file, if it is then you add 1 to wordCount. In addition you could use a char array to store the output for 5.5, but thats pointless for this program as you can simple cout it 1 char at a time as it comes out.