# Thread: Converting from double to int

1. ## Converting from double to int

Previously I have declared b as a double and I now I want to convert back to int. Here is the code:
Code:
`int c = static_cast<int>(b);`
Does this mean that now b is now a int where c = b? Am I right?

2. Code:
```double b = 2.5764;
int c = 0;
c = (int)b;   //the int tells the comiler that you MEANT to convert from a double to and int
//and the compiler won't warn you that you are losing some precision in the conversion

// c == 2 == true
// b == 2.5764 == true;```

edit: actually "(int) b" means evaluate 'b' as an integer

3. Does this mean that now b is now a int where c = b?
Code:
```double b = 3.5;
int c = static_cast<int>(b);

cout<<c<<endl;  //3
cout<<b<<endl;  //3.5```
c != b

In addition, you might think you have 3.0 in a double variable, but really you have 2.9999999999999, and when you cast that to an int, you will get 2, and 2 != 2.99999999.

4. Does this mean that now b is now a int where c = b? Am I right?
No, that statement takes the value of b, casts it to an int without changing the value of b, and stores that value in another variable c.

Therefore, c is an int, and b is still a double.