Thread: Converting from double to int

  1. #1
    T-Mac wiz23's Avatar
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    Converting from double to int

    Previously I have declared b as a double and I now I want to convert back to int. Here is the code:
    Code:
    int c = static_cast<int>(b);
    Does this mean that now b is now a int where c = b? Am I right?

  2. #2
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    Code:
    double b = 2.5764;
    int c = 0;
    c = (int)b;   //the int tells the comiler that you MEANT to convert from a double to and int
                      //and the compiler won't warn you that you are losing some precision in the conversion
    
    // c == 2 == true
    // b == 2.5764 == true;

    edit: actually "(int) b" means evaluate 'b' as an integer
    Last edited by misplaced; 04-13-2005 at 04:27 AM.
    i seem to have GCC 3.3.4
    But how do i start it?
    I dont have a menu for it or anything.

  3. #3
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    Does this mean that now b is now a int where c = b?
    Code:
    double b = 3.5;
    int c = static_cast<int>(b);
     
    cout<<c<<endl;  //3
    cout<<b<<endl;  //3.5
    c != b

    In addition, you might think you have 3.0 in a double variable, but really you have 2.9999999999999, and when you cast that to an int, you will get 2, and 2 != 2.99999999.
    Last edited by 7stud; 04-13-2005 at 04:55 AM.

  4. #4
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    Does this mean that now b is now a int where c = b? Am I right?
    No, that statement takes the value of b, casts it to an int without changing the value of b, and stores that value in another variable c.

    Therefore, c is an int, and b is still a double.

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