Thread: Cin Masking

If I understand your question correctly, then yes.
Consider the following code

Code:

#include <iostream>

using namespace std;

int main()
{
	int i = 0;
	char string[7];
	cout << "Please input a short string of characters: ";
	cin >> string;
	while (string[i] != NULL)
	{
		string[i] += 15;
		cout << string[i];
		i++;
	}
	cout << "\n";
	return 0;
}

It will rotate your input by 15

If I understand you correctly, as the user types input, you want a character they type to appear as a * rather than the key they actually typed. As far as I know, a C++ console program doesn't know what the user has done until they hit return. However, in other languages like javascript, you can detect keypresses and change their output, so I would think there would be something similar if your program was a windows program.

The answer is yes and no It really depends on your OS and your compiler. What you have to do is to take it out of "cooked" mode and put it into "raw" mode. You can not do this with cin. But it can be done with the buffer cin points to. What you are looking to do can be accomplished with getch() if your OS/Compiler supports it.

Again it depends on your OS and Compiler. If your compiler has getch() then you can read one character at a time into an array. Then each time you output a '*'. However you must then take care of things like the user hitting the backspace or hitting function keys or what not. One the user hit's return you then take your character array and convert it to an integer and compare it.

As was mentioned before, you're looking for raw input rather than cooked. Also try searching for non-canonical (raw) vs canonical (cooked) input. If you're programming for windows/dos it's rather easy. For *nix systems it get's a bit more complicated.