Thread: Printing numbers in hex format

I need to pass the std::cout to a function so that numbers print in hex and uppercase and 8 digits are printed with 0 fill. I got it to print in hex and uppercase, but I can't figure out the 0 fill. It goes like

Dump(std::cout);

Dump() can't be changed though, so everything I want done has to be set for the stream I'm passing in.

Any ideas?

I'm glad you said give ideas because that's all I got! lol.

Code:

#include <iostream>

using std::cout;
using std::endl;

int main()
{
    // Outputting some ideas
    cout << "0x";
    cout.width(8);
    cout.fill('0');
    cout << "CFF" << endl;
    return 0;
}

Thanks for replying. I can get it working like that, but I can't get it to set the stream like that and pass it off to a function.

Do a board search on displaying hexadecimal. There've been several threads discussing how to do it, and you should find an exaplanation and even some example source code for turning a number into a character string consisting of hex digits.

Thanks. I forgot to mention that I'll be printing unsigned long values, so I can't use a string of characters.

Well, let me back up then. I might not be understanding how the flags work. For instance, I was thinking this code would print 123 in hex format:

Code:

#include <iostream>
#include <iomanip>

int main()
{

    std::cout.setf(std::ios::hex | std::ios::uppercase);
    std::cout << 123 << std::endl;

    std::cout << std::setiosflags(std::ios::hex | std::ios::uppercase);
    std::cout << 123 << std::endl;

    return 0;

}

But, it just prints 123 in the normal base 10 format. Where am I going wrong?

The %x is for printf, since this is the C++ forum we are using stream insertion

There is a state modifier called hex that is found in the std namespace. It works like so:

Code:

std::cout<<std::hex<<123<<std::endl;