Thread: Integer displaying crazy numbers issue

  1. #1
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    Unhappy Integer displaying crazy numbers issue

    O.K. First off I would like to explain that I am making a simple game. I check my syntax, and I check it often. I thought at first my problem only existed in my game code, but I then found out through testing that it is with all code. I am using Dev-C++ (Newest Version) and here is a sample code. Try it and you will see what I mean.
    Code:
    #include <iostream>
    using namespace std;
    int main();
    {int gold;
    gold == 45;
    cout<<"To display your current amount of gold hit the return key.";
    cin.get();
    cout<<"You currently have "<<gold<<" gold.";
    cin.get();}
    It displays 2 sometimes. At other times it displays like 21309874 or something like that. Somebody please help me!!

  2. #2
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    You are using the equality operator instead of the assignment...
    gold == 45 // wrong...
    gold = 45 // right

    The reason why it shoots strange numbers because it is trying to see if it equals 45 as in an if statement. When you declare any variable it is assigned an address and that address might contain garbage information that was used from a previous program.

  3. #3
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    Yeah, == evaluates something for example:
    Code:
    if(x==5)
         {
             Do something...
         }
    but just plain = assigns a value to a variable or character, etc.
    Code:
    int x=10;
    I used to do that alot

  4. #4
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    Its SOOOOO increadbly easy to make small syntax errors and logical errors like that. Even for intermediate and expert programmers - and you end up bashing your head off your keyboard trying to figure it out. Sometimes you need a fresh set of eyes because the longer to work at it the harder it becomes. Iv found too its easy just to walk away for a little bit then come back and take another peek.

    I have a funny story about a problem with Microsoft Visual C++ - I would have to post code and explain thought - let me know if your interested - haha. It had to do with my Energy encryption algorithm.

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    Talking Hm....

    I see...I am new to this, but I was once told by someone in the forums(dont remember who)to use == if you do not have a very strong wish not to. Oh well, I must have misunderstood them. As for the story, go ahead if you wish

  6. #6
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    Question More help...

    OK...so lets say I get that figured out so it works correctly. When it displays gold, it displays the amount I meant for it to. Now lets say I want to make it so that gold can be spent on an item. I figured it would look something like
    Code:
     gold - 50 = gold
    So lets start from scratch. I want it so that the person drops 10 gold every time they enter l. I also want them to pick up 10 gold every time they enter 2. So I figure the code should resemble this:
    Code:
    #include<iostream>
    #include <string>
    using namespace std;
    int main();
    {int gold;
    string loseorgain;
    gold = 1000;
    start:
    cout<<"Enter '1' to gain 10 gold or '2' to lose 10 gold.";
    cin>> loseorgain;
    cin.ignore();
    if (loseorgain==1) {"<<gold<<" + 10 = gold}
    else if (loseorgain==2){"<<gold<<" - 10 = gold}
    else {}
    cout<<"You now have "<<gold<<" gold.";
    cin.get();
    goto start;
    Even though the code doesn't work, you should be able to get what I am asking. Thanks for the help earlier, and thanks to whoever will help me this time
    Last edited by Razorblade Kiss; 12-20-2004 at 10:17 PM. Reason: Syntax Errors in code

  7. #7
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    Now lets say I want to make it so that gold can be spent on an item. I figured it would look something like
    Code:
    gold - 50 = gold
    No. The right side of the equation is always assigned to the left side, therefore your code should be

    Code:
    gold = gold - 50
    Or there's a shortcut version:

    Code:
    gold -= 50

  8. #8
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    ok...pardon my stupidity, but how would that go in the code mentioned above?

  9. #9
    Handy Andy andyhunter's Avatar
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    Code:
    if (loseorgain==1){
    
          gold+= 10;
    
    }else if (loseorgain==2){
    
          gold -= 10;
    }

  10. #10
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    Errors all over the place

    OK, so I entered the code, hit compile & run. Errors, errors, errors...Where have I gone wrong? Why can't it be easy!
    Code:
    #include<iostream>
    #include <string>
    using namespace std;
    int main();
    {
    int gold, loseorgain;
    gold = 1000;
    start:
    cout<<"Enter 1 to gain gold, or 2 to lose gold.";
    cin>> loseorgain;
    cin.ignore();
    
    if (loseorgain==1){
    
               gold+= 10;}
    else if (loseorgain==2){
    
              gold-= 10;}
    Where is the freaking error?

  11. #11
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    Where is the freaking error?
    You tell us. Post the error messages.

    I can see straight away that you don't even have matching }'s for each {.

    edit: You also specified int as the return type for main, yet you never return anything. Place "return 0;" at the end of your code, before you close the main function.

  12. #12
    Handy Andy andyhunter's Avatar
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    Code:
    int main()  ; //no semicolon goes here
    That is your error. Remove it!!!!

  13. #13
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    (Remove just the semicolon)

  14. #14
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    line 5:syntax error before {
    line 7:ISO C++ forbids declaration of 'gold' with no type
    line 8:syntax error before :
    line 10:syntax error before >>
    line 11: syntax error before .
    line 21: syntax error before <<
    line 22:syntax error before .

    Lots of errors...

  15. #15
    Handy Andy andyhunter's Avatar
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    BTW anyone else notice the program doesn't end? No escape clause as I like to say

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