Thread: Putting the function body with the prototype

  1. #1
    C/C++ homeyg's Avatar
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    Putting the function body with the prototype

    In the code below, I was testing to see if putting the function body with the prototype would work. I'm assuming this makes it inline like it would in a class?

    Code:
    #include <iostream>
    
    using namespace std;
    
    int mult(int num)
    {
      return num*num;
    };
    
    int main()
    {
      int number;
      cout<<"Input a number. ";
      cin >>number;
      cout<<"That number squared is: "<<mult(number)<<endl;
      system("PAUSE");
      return 0;
    }

  2. #2
    & the hat of GPL slaying Thantos's Avatar
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    Only one thing can ask the compiler to inline a function and that is the inline keyword.

    Its perfectly ok to put the body with a prototype in the manner you did above. Of course you don't need the ; after the function's closing }

  3. #3
    C/C++ homeyg's Avatar
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    Yeah, but if the semicolon wasn't there, wouldn't that be negating the purpose of the prototype (like if I had three functions up there, to not have to rely on order of declaration)?

  4. #4
    Code Goddess Prelude's Avatar
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    >I was testing to see if putting the function body with the prototype would work.
    It works as long as the function is defined before its use. This is because a definition is also a declaration, but a declaration is required before use. Now say that 3 times fast.

    >I'm assuming this makes it inline like it would in a class?
    No, outside of an inline class definition, you need to use the inline keyword to suggest to the compiler that you want the function inlined. Though it's free to ignore you, and it probably will because the programmer is notoriously bad at determining these things.
    My best code is written with the delete key.

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