Thread: Code question..

Hi i have made this simple code:

Code:

#include <iostream>
#include <stdlib.h>
#include <iomanip>

using namespace std;

int main(int argc, char *argv[])
{

int MyArray[10];


for(int i=0;i<10;i++){
    cout<<setw(7)<<"MyArray["<<i<<"] = "<<i<<endl;
    cout<<setw(16)<<"Value for Element "<<i<<"  = "<<1+rand()%10<<endl;
 

}    
  system("PAUSE");	
  return 0;
}

my problems are:

1. i want to make an Histogram, for the random value..
for example if i have a value 10, i want to print 10 asterisks..

2. how to set the output to this:

MyArray[] Value Histogram
0----------> 4 ----> ** **
1----------> 2 ----> **


Thanks in advance..

use a nested loop, two loops deep. The outer loop will initialize a variable to control how many times through the inner loop you will go. the inner loop will output a single character (asterix) each time through the loop. You can put a space between each group of two character if you wish. When output for inner loop completed go to the next line before starting next time through inner loop.

Originally Posted by swoopy

>1. i want to make an Histogram, for the random value..
>for example if i have a value 10, i want to print 10 asterisks..

Another idea is to make a string filled with *'s. Then use the substr() function to display a certain number of *'s based on the value in MyArray[i].

This method is limiting. What if I only have 20 '*' in my string and the value is 21?

the number of * in the string could be determined based on user input.


int size;
cout << "enter # of * to use as max per line" << endl;
cin >> size;
string str;
for(int i = 0; i < size; ++i)
str += "*";

or better yet:

string str(size, '*');

should work.

for( int j = 0; j < 10; ++j )
cout << string(MyArray[j],'*') << endl;

well done.