Thread: Fibonacci sequence output statement

HI i need help writing my output statement for fibonacci sequence so far i have how to get the sequence and i must output all array elements with 5 elements per line and in a field width of 10....can someone help me?

here is what i have so far:
for (int = 0; i < 30; i++)
{
cout << setw(10) << fib[i];
}
cout << endl;

Code:

for (int = 0; i < 30; i++)
{
   cout << setw(10) << fib[i];
   if (                  )  //Look up the modulus operator
      cout << endl;
}
cout << endl;

Besides using the modulus operator, you could instead keep a count, and when it reaches 5, output a newline.

Check swoopy's post again. There are a couple methods you could use to accomplish this: mod (%) and a resetable counter.

Use code tags...

Anyway, I don't quite understand the problem. Is the formatting correct?
The Fibonacci sequence itself starts with a pair of ones: { 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, etc }

Code:

if((i + 1) % 5 == 0) 
... or ...
if(i % 5 == 4)

That ought to do it.

Well, it can be convenient to define the 0th Fibonacci number F[0] = 0, and in fact, if you use the closed form function to generate Fibonacci's, then F(0)=0, and F(1)=1, so the first (1th) term is really 1, although you can put a 0 before it (obviously) without modifying the sequence.

So, F(n) = [(1+sqrt(5))^n - (1-sqrt(5))^n]/[sqrt(5) * 2^n]
Plugging in:
F(0)=0
F(1)=1
etc

Cheers