Thread: Complex number in qudratic equation C++

  1. #1
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    Complex number in qudratic equation C++

    hi I need help with this program, I have to write an easy code for complex number thank you

    if I put a=1, b=2. c=2 then I should get x=-1+j.1 and y=-1-j.1. I am an engineer so I use j instead of i.

    #include <iostream>
    #include <math.h>

    using namespace std;

    int main()

    {
    float a=0.0;
    float b=0.0;
    float c=0.0;
    float d=0.0;
    float x=0.0;
    float y=0.0;

    cout <<"value of a:";
    cin>>a;
    cout <<"value of b:";
    cin>>b;
    cout <<"value of c:";
    cin>>c;

    d=sqrt(b*b-4*a*c);
    x=(-b+d)/(2*a);
    y=(-b-d)/(2*a);

    if (x==y)
    {
    cout<<"Both roots are equal\n";
    }
    else(x!=y)
    {
    cout<<"The roots are not the same\n";
    }

    cout<<x;
    cout<<y;
    cout<<"\n";

    return 0;

    }

  2. #2
    and the hat of int overfl Salem's Avatar
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    Come back when you've learnt to read
    http://cboard.cprogramming.com/showthread.php?t=13473
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
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  3. #3
    carry on JaWiB's Avatar
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    Code:
    else(x!=y)
    {
    cout<<"The roots are not the same\n";
    }
    Try just 'else' not with the (x!=y)
    "Think not but that I know these things; or think
    I know them not: not therefore am I short
    Of knowing what I ought."
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  4. #4
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    man I just asked u didnt had to eat my head
    is that forum is for when u don know ask other people thats what I am doing

    now thank you jawib

  5. #5
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    Eating heads?? Salem pointed out that if you post code you use codetags. Nothing more, nothing less, but some people can/will be annoyed when you post code without codetags, especially since there is a sticky saying that you should/must use codetags.

  6. #6
    & the hat of GPL slaying Thantos's Avatar
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    also realize that there is a standard complex class in <complex>

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