I've made(with tonz of help from you guys) a program that prints random numbers.
Now it is so that I want to somehow change these numbers!
So when I for example get a 1 I want to change that into for example the word bear, so I can cout it out like bear if the program returned 1.
(My program is limited to only using the 1-9 numbers)
I hope you understand me, I'm not to good in english
Where's the code?
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
As you see its not completed. But you do get what I want?Code:#include <conio.h> #include <cstdlib> #include <iostream> #include <stdio.h> #include <time.h> using namespace std; int number_generator() { return rand()%10+1; } int main() { srand(time(NULL)); do { //Val av attack int input; cout << "Vad vill du attackera med?" << endl; cout << "1. Sax" << endl; cout << "2. Sten" << endl; cout << "3. Påse" << endl; cin >> input; } while( yorn == 'y'); getch(); return 0; }
Code:char *creatures[] = { "Sax", "Sten", "Påse", // some more }; cout << creatures[number_generator()] << endl; cout <<
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
Alright I didn't get much of that but I'll try!
What I really want is something like this:
A function returns a variable with a number. I want , preferably in a function, to make that number into a word like "sax". So it wont print the number, it should print the word!
Salem used an array. So, characters[0] is Sax, characters[1] is Sten, and characters[2] is Påse.
Then, you use characters[random].
Note that because each string is already an array, you have an "array-of-arrays".
These are not array variables:
X1
X2
X3
These are array variables:
X[1]
X[2]
X[3]
Now, we can have X[n], where n is another variable. If n is random, we will randomly select one of the variables in the array.
Another way to do this is with if-statements, or switch.
[EDIT] - Salem's solution should work if you get the syntax right... You should be able to display the "word".
Last edited by DougDbug; 09-29-2004 at 01:05 PM.
I see
You could also use a simple switch statement. For example:You could also put that in a function and return the string instead of using cout to display it. The array idea is a little cleaner, but if you don't know arrays, it might be easier to just use a switch or even if/else statements.Code:switch (number) { case 1: cout << "Sax"; break; case 2: cout << "Sten"; break; case 3: cout << "Påse"; break; default: cout << "ERROR"; break; }
Thanks a lot !! =D =D Going to try this later on today after class!!
