Thread: Passing arguments to function...

#1) place a cout << fname << endl; after the line fname = argv[1]; to be sure you have valid information in fname.

#2) you need to declare an ifstream object in order to associate with a file using the () operator, say maybe.

ifstream fin(file)

rather than

ifstream(file);

then be sure fin opened file before trying to use it.

ok i'm sorry about that ive changed the original post...that is how i've done it in my original code...ok 2 things...

1) does argv[1] indicate the first or second argument to main...i mean when i run my program (astar) i want to write:

astar inputfile

where it is understood that inputfile is the name of the file...so is that argv[0] or argv[1]...i tried argv[0] and i get a segmentation error...argv[1] doesn't work as it hangs...

2) if i hardcode the filename it always works...e.g. if i write:

Code:

ifstream fin ("inputfile.txt");

this always works...i just don't want to hardcode the name of the file...

Regards,

Farooq

argv[1] should be inputfile in your example. check it out by running the program with the command line arguments you have listed. comment out the call to readfile() and put a cout << argv[1] << endl; in the program to prove it. Put in a cout << fname << endl; after you assign argv[1] to fname to be sure you have the same information int fname.

ya it works when i use:

astar inputfile.txt

is there someway where i can just make it: astar inputfile

i really don't know if it will be a text file or what...in fact the assignment question just says it will be run as:

astar inputfile

Regards,

Farooq

you could provide code to append the .txt string on to argv[1].

you could ask user to enter extension type of the file and append it to the end of argv[1].