Thread: Newbie Question

Originally Posted by sand_man

also, a function like this

Code:

void foo();

takes unknown amount of arguments. You should change it to.

Code:

void foo(void);

That is true only in C. In C++,

Code:

void foo();

is valid and probably more accepted.

to Elhaz

this third case statement first of all does exit the programm even it doesnt looks like it ,and second i try to avoid that you enter a letter instead of a number for the temperature ,which obviously would print out some stupid not wanted strings ,but yes there is still the a lill problem with comparing enterd letters and number while you already choose your temp .
Anyways as you can see i think its not to bad for someone that didnt had done something in C++ for 5 years ,guess its getting more as time to find and read some books to get ahead ,but regardless that ,thank you all with the help i gave me and the ideas of how to manage it all .

Hoschi

Hi Hoschi,

I see it now. The exit (0) is a library function. I didn't look at it (think about it) carefully enough. My mistake. I'll try to be more careful about "piping up" in the future.

Don't know how much I helped... you actually helped me more just by giving me something read and think about.

Thanks