Setting strings

**LloydUzari** · 07-29-2004

Im new to programming(started 2 weeks ago) and am trying to make a poker program for a first project. I am using a function rplc() aka replace to change a an inputed ID to the cards name. I was wonder how I could set an array to equal a string. I understand how it is input, but how to you set it? I have been trying to do things like [array] = [string], and with quotes and such, but its just printing out e instead of the value I put, so I know it isnt working. Would I have to do each letter seperatly set? If so, Im gonna have to find a better way, because that would take me over 700 lines just for that

**Salem** · 07-29-2004

How about

Code:

char *suits[] = {
  "clubs",
  "diamonds",
  "hearts",
  "spades"
};

Then you can either do

Code:

char card_suit[10];
strcpy( card_suit, cards[2] );

Code:

char *card_suit;
card_suit = cards[2];

**LloydUzari** · 07-29-2004

Maybe I should be more specific...

Heres an example of the code:

Code:

if(cardID = 0)
{
  [coding that changes id '0' to 'Two of Hearts']
}

Im having problem of what to put in there, Ive been thinking of just using an array that this part sets, and then after all 52 of these blocks(one for each card) put either return [array];(if thats proper syntax

) or just have the array global and have it print out from the array directly.

btw: Im aware that that is 100+ lines, but copy paste works wonders for that. each letter seperate though is just way too...

**Salem** · 07-29-2004

If card_id is 0..51 say, then use
card_id % 13
to get the face value, and
card / 13
to get the suit value

**LloydUzari** · 07-29-2004

I see what you mean, but it still doesnt seem to fit my coding... Heres what Im thinking about, using a global variable:

Code:

if(cardID = 0)
{
  cardNAME = Two of Hearts;
}

Basically, I need to find a way to make that legal. Is there a way to auto set a char array to have that value, or am I gonna have to go looking more into the string header?

**Tman** · 07-29-2004

strings are nice, but if you don't want to use them, strcpy() is the way to go.

Code:

strcpy (cardNAME, "Two of Hearts");

Should do it, assuming you have the array big enough to hold all the characters. I don't think allocating an array each time is worth it.

**LloydUzari** · 07-29-2004

Thanks, I used that, but now it seems to have an error of not running again. Will that function overwrite itself, or do I have to clear out the array before it will copy ontop of it again? If so, is there a compiler that will allow you to put the null value(the noob knows what it is ^^), because it seems whenever I try to, it just puts '?' instead of it in the editor window, and my compiler changes it to a '?' when it loads it, so I cant set it. I have tried setting it to NULL, but it just runs an error and doesnt work.

**elad** · 07-30-2004

Assume cardNum is an int, with valid values of 1 to 52. There's no reason you couldn't use the following approach.

if(cardNum == 1)
cout << "Ace of spades" << endl;
else if (cardNum == 2)
cout << "two of spades" << endl;
//same for 3 to 50
else if(cardNum == 51)
cout << "Queen of Clubs" << endl;
else
cout << "King of Clubs" << endl;

It might not be the most sophisticated approach, but it allows you to convert a number representing a card to a correlated string representing a card, and the more sophisticated approaches will come later. To do it in a more sophisticated fashion I'd learn about enumerated constants, switch statements, structs/classes, overloading operators, friend functions, STL maps, etc.

**JaWiB** · 07-30-2004

what about something like this?

Code:

#include <iostream>

enum { DIAMONDS, HEARTS, CLUBS, SPADES } ;
char *strsuit[] = {
  "diamonds",
  "hearts",
  "clubs",
  "spades"
};




int main()
{
  unsigned int cardsuit;
  std::cin>>cardsuit;
  if (cardsuit<=3)
    std::cout<<strsuit[cardsuit]<<std::endl;
}

In that case 0 is diamonds, 1 is hearts, and so on. It wouldn't be hard to allow strings to be inputted (then setting cardsuit to the appropriate number)

You could also do something similar for the number of the card, ie

Code:

enum { ONE, TWO, /*...*/, JACK, QUEEN, KING, ACE }

**C++Child** · 07-30-2004

No need 4 arrays! How 'bout this?

Code:

srand(time(NULL));
int cardnumber = rand() % 13 + 1;
int suit = rand() % 4 + 1;
if(cardnumber == 1)
cout<<"Ace of ";
else if(cardnumber == 11)
cout<<"Jack of ";
else if(cardnumber == 12)
cout<<"Queen of ";
else if(cardnumber == 13)
cout<<"King of ";
else
cout<<cardnumber<<" of ";
if(suit == 1)
cout<<"Spades"<<endl;
else if(suit == 2)
cout<<"Hearts"<<endl;
else if(suit == 3)
cout<<"Clubs"<<endl;
else
cout<<"Diamonds"<<endl;

Do that 4 more times with different variables and then u'll have the hand. In order to check if the hand is worth points the && operator is useful. Like

Code:

if(card1 == card2 - 1 && card2 == card3 - 1 && card3 == card4 - 1 && card4 == card5 - 1 && suit1 == suit2 && suit1 == suit3 && suit1 == suit4 && suit1 == suit5){//You got a straight with all of the cards the same suit}

**Princeton** · 07-30-2004

>>How 'bout this?
Are you sure that it is correct? Can you verify that it is as easily as an array based solution? A simple boundary check and array index is provably easier to get right than if..else if..else chains or a long logical expression.

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