I've been trying to figure out how to reverse the elements in my array. But im drawing a blank. Any help would be greatly appreciated.
Code:#include <iostream> using namespace std; void reverse(int a[],int size );//prototype int main() { const int size=10; int a[size]={1,2,-3,-4,-5,-6,7,8,-9,10}; reverse(a,size);//call return 0; } void reverse(int a[], int size) //reverse order of elements in array { for(int i=0;size<i;i++){ cout<<a[i]; } }
Well, I'll give you a hint:
You still have the same number of elements right?
You might want to look at using the '--' (decrement) operator and start your counter not at zero but a different value.
Hope that helps!
Nick.
Ok, what you said made a lot of sense and I altered the code but now I get this inifinite loop!
A little hint on why this may be occuring would be appreciated. thanks.Code:void reverse(int a[], int size) //reverse order of elements in array { for(int i=size;size>0;--i){ cout<<a[i]; }
a little hint: if you have size elements in your array, they are indexed from 0 to size-1
I'm thinking something like this:
I think it will work. To me it seems like the most logical way, but it's probably not the most efficient way.Code:void Reverse(int *Array,int Size) { int LastIndex=size-1; int TempInt=0; if (!Array) return; for (int Loop=0;Loop<=(LastIndex/2);Loop++) { TempInt=Array[Loop]; Array[Loop]=Array[LastIndex-Loop]; Array[LastIndex-Loop]=TempInt; } }
Basically it works by looping through the first half of the array and swapping each element with its far counterpart.
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Your infinite loop is because of the test condition in the for loop. Replace "size > 0" with "i > 0" and it will work. Oh yeah, in the body of the loop, replace "a[i]" with "a[i-1]" to access the correct element. You've got everything right.Originally Posted by dantestwin
I got it to work. Thanks Nick.
