Thread: Works in MSVC++ 6.0 but not in Dev-C++

Hi. Does anyone have any idea why the following code works in MSVC++ 6.0 but not in Dev-C++ 4.9.8.0? Thanks.

Code:

#include<iostream>
#include<iterator>
#include<vector>
#include<string>

using namespace std;

template <class T>
class Set
{
  public:
    void add(const T& anItem);
    bool has(const T& targetItem);
    friend ostream& operator <<(ostream& os, Set<T>& aSet)
    {
      vector<T>::iterator anIt;
      for(anIt=aSet.theMembers.begin();anIt != aSet.theMembers.end();anIt++)
      {
        os<<(*anIt)<<" ";
        os<<endl;
      }
	  return os;
    }
  private:
    vector<T> theMembers;
};

int main()
{
  Set<int> s1;
  s1.add(10);
  cout<<s1;
  cout<<s1.has(10)<<endl;
  system("pause");
  return 0;
}

template <class T>
void Set<T>::add(const T& anItem)
{
  theMembers.push_back(anItem);
}

template<class T>
bool Set<T>::has(const T& targetItem)
{
  vector<T>::iterator anIt;
  
  for(anIt=theMembers.begin(); anIt != theMembers.end(); anIt++)
  {
    if((*anIt)==targetItem)
      return true;
  }
    return false;
}

Change all occurences of

Code:

vector<T>::iterator anIt;

to

Code:

typename vector<T>::iterator anIt;

The standard says that any type which is dependent on a template paramater, must be prefixed by the keyword typename.

The type of "anIt" is "vector<T>::iterator". This type is dependent on the template parameter T, so you have to use typename in front of it.

>> ... why the following code works in MSVC++ 6.0 but not in Dev-C++ 4.9.8.0?
Because gnu/g++ is a more standards conforming compiler.

gg