Thread: passing a 2dim array to a funct

by doing that you are actually passing through a 3d array. If you want to pass in a 2d do this:

Code:

void foo( char p[][100] )
{ 
     //
}

where 100 is the size of the second dimension.

edit: the 100, could be any number and SHOULD be the size of YOUR array's second dimension

> could be any number and SHOULD be the size of YOUR array's second dimension
All minor dimensions MUST match.

There are 3 different ways of writing the same thing when it comes to passing multi-dimensional arrays to functions.

Code:

/* all these are the same */
void foo( char p[50][100] );  /* size of 1st dim is entirely optional */
void foo( char p[][100] );
void foo( char (*p)[100] );   /* watch the (), char *p[100] is a different animal */

This is handy, because the first one permits a rather simple and dead easy to remember rule called "copy and paste"

If you had
int arr[X][Y][Z];

You can simply copy and paste that into a function parameter
void foo ( int arr[X][Y][Z] );

And call it with
foo( arr );

Just like you would do for any non-array type really

If you want to go round chopping the X out of the function definition and declaration, then that is up to you. Though some lint tools will remark that the X size is redundant.