Ok, here is the current work (sorry about the formatting... don't know html tags to display it properly on this forum). I have few issues still, but overall I am pleased ( this is my first Computer Science class). My main problems still are the following:

1. Getting the program to immediately give an error if the input

given is not a-f instead of it asking for the integers first.

2. For case 'c', I need to find the average of the 3 integers

converted to the floating point average. The compiler

warns me that it is coverting it with a possible loss of

data. Am I doing this right or is there another way?

3. The inability to handle a zero input for case 'a' is still

present as I focused all my energy I finishing the rest

of the program first. I will be working on that in the

meantime.

4. Anything else that you feel like mentioning.

Code:

#include <iostream.h>
#include <math.h>
int main()
{
int val1;
int val2;
int val3;
int first;
int second;
int third;
char option;
float sum;
int same;
int even = 0;
int odd = 0;
float num1 = 0;
float num2 = 0;
float num3 = 0;
// Title, Input
cout << "Integer Calculation Program\n" << endl;
cout << "Enter a single character a-f\n" << endl;
cin >> option;
cout << "Enter three integer values." << endl;
cin >> val1 >> val2 >> val3;
switch (option)
/*
Case 'a' compares the 3 integers, assigns the values in order from smallest
to largest to the variables first, second, and third, and then displays
the output to the user.
*/
{
case 'a' :
if (val1 <= val2 && val1 <= val3 && val2 <= val3)
{
first = val1;
second = val2;
third = val3;
}
if (val2 <= val1 && val2 <= val3 && val1 <= val3)
{
first = val2;
second = val1;
third = val3;
}
if (val3 <= val1 && val3 <= val2 && val2 <= val1)
{
first = val3;
second = val2;
third = val1;
}
if ( val3 <= val1 && val3 <= val2 && val1 <= val2)
{
first = val3;
second = val1;
third = val2;
}
cout << first << " " << second << " " << third << " " << endl;
break;
/*
Case 'b' calculates the absolute values of the 3 integers and then
displays the output to the user.
*/
case 'b' :
val1 = abs (val1);
val2 = abs (val2);
val3 = abs (val3);
cout << val1 << ", " << val2 << ", and " << val3
<< " are the absolute values of your input." << endl;
break;
/*
Case 'c' adds the 3 integers and then finds the average floating point
value of their sum by dividing by 3.
*/
case 'c' :
sum = (val1 + val2 + val3) / 3.0;
cout << sum << " is the average of the three integers given."
<< endl;
break;
/*
Case 'd' compares the 3 integers and determines and displays the number of
the values that are the same.
*/
case 'd' :
if (val1 == val2 && val2 == val3)
same = 3;
if (val1 == val2 && val3 != val1)
same = 2;
if (val2 == val3 && val1 != val2)
same = 2;
if (val3 == val1 && val2 != val3)
same = 2;
if (val1 != val2 && val2 != val3 && val1 != val3)
same = 0;
cout << same << " of the integer values are the same."
<< endl;
break;
/*
Case 'e' determines how many of the 3 integer values are even and how many
are odd and then displays the information to the user.
*/
case 'e' :
if ((val1 %2) == 0)
even++;
else
odd++;
if ((val2 %2) == 0)
even++;
else
odd++;
if ((val3 %2) == 0)
even++;
else
odd++;
cout << even << " of the values are even." << endl;
cout << odd << " of the values are odd." << endl;
break;
/*
Case 'f' determines if the 3 integers are positive, and then adds the
positive integers together and divides them by 3.0 to determine the
float point average of the positive integers.
*/
case 'f' :
if (val1 > 0)
num1 = val1;
if (val2 > 0)
num2 = val2;
if (val3 > 0)
num3 = val3;
sum = (num1 + num2 + num3) /3.0;
cout << sum << " is the floating point average "
<< "of the positive integers." << endl;
break;
/*
If any character besides a-f was given, then after entering the 3 integer
values, the program gives an error message informing the user of the
mistake.
*/
default : cout << "Not a valid option. You did not choose "
<< "a character a-f." << endl;
}
return 0;
}