// The program below gives the output "10/010/01"
//But I only want the dd of mm/dd/yy.
//How do I extract just the day? Thanks.
#include <time.h>
#include <iostream.h>
#include <string.h>
int main()
{
char datebuf[9];
char day[2];
char *digit1=&datebuf[3];
char *digit2=&datebuf[4];
_strdate(datebuf);
strcpy(day,digit1);
strcat(day,digit2);
cout<<day<<endl;
return 0;
}
> char day[2];
You need at least 3 chars to store "dd\0" - gotta remember that \0 when dealing with 'C' style strings
> char *digit1=&datebuf[3];
> char *digit2=&datebuf[4];
Ok, but unnecessary...
> strcpy(day,digit1);
> strcat(day,digit2);
This is where the problem is - using strcpy and strcat to copy single chars
Try
Or if you insist on using a str... functionCode:day[0] = datebuff[3]; day[1] = datebuff[4]; day[2] = '\0';
Code:strncpy( day, &datebuff[3], 2 ); day[2] = '\0';
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
Thanks so much, Salem.
