Initialization is translated to a copy construction even if in the syntax
type name = existing;
This line has the same effect as
type name(existing);
Initialization is translated to a copy construction even if in the syntax
type name = existing;
This line has the same effect as
type name(existing);
All the buzzt!
CornedBee
"There is not now, nor has there ever been, nor will there ever be, any programming language in which it is the least bit difficult to write bad code."
- Flon's Law
