Thread: wrong result?

  1. #1
    Registered User o0o's Avatar
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    Dec 2003
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    Unhappy wrong result?

    Code:
    #include<iostream>
    #include<conio.h>
    
    using std::cout;
    using std::cin;
    using std::endl;
    
    // functions prototypes
    
    double Celsius( double );
    double Fahrenheit( double );
    
    int main()
    {
        // declare varibales
        
        double tempCelsius, tempFahrenheit;
        
        // read temperatures
        
        cout<< "Enter temperature in Celsius scale:";
        cin>> tempCelsius;
        cout<< "\nEnter temperature in Fahrenheit scale:";
        cin>> tempFahrenheit;
        
        // display results
        
        cout<< "\n" << tempCelsius << "c = " << Celsius( tempFahrenheit ) << "F";
        cout<< "\n" << tempFahrenheit << "F = " << Fahrenheit( tempCelsius ) << "c";
            
    getch();
    }
    
    // definitions of Celsius() & Fahrenheit()
    
    double Celsius( double valueA )
    {
        return (5/9)*(valueA-32);
    }
    
    double Fahrenheit( double valueB )
    {
        return (9/5)*valueB+32; 
    }
    This code gives the right answer for celsius temperature when converted from fahrenheit scale but centigrade scale to fahrenheit it gives only 0F as answer.

    help needed/

  2. #2
    Registered User Codeplug's Avatar
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    >> (5/9)
    Integer division.

    gg

  3. #3
    Senior Member joshdick's Avatar
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    5/9 = 0
    5.0/9.0 = .5555555555555...
    FAQ

    "The computer programmer is a creator of universes for which he alone is responsible. Universes of virtually unlimited complexity can be created in the form of computer programs." -- Joseph Weizenbaum.

    "If you cannot grok the overall structure of a program while taking a shower, you are not ready to code it." -- Richard Pattis.

  4. #4
    Registered User o0o's Avatar
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    just a slight change makes it work.
    only adding double or static_cast<double> doesn't give the required results on my dev c++ compiler.
    y? is that?


    Code:
    double Celsius( double valueA )
    {
        return (( double )(5.0/9.0)) *(valueA-32);
    }
    double Fahrenheit( double valueB )
    {
        return (( double )(9.0/5.0)) *valueB+32; 
    }

  5. #5
    and the hat of int overfl Salem's Avatar
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    Perhaps you should choose better names
    double Celsius( double valueA )

    Now is that to Celsius or from Celsius?
    And valueA doesn't help. If it were either c or f for example, that might be more of a clue.

    Code:
    #include<iostream>
    
    using std::cout;
    using std::cin;
    using std::endl;
    
    // functions prototypes
    double Fahrenheit_to_Celsius( double f );
    double Celsius_to_Fahrenheit( double c );
    
    int main()
    {
        for ( double centigrade = 0.0 ; centigrade <= 100.0 ; centigrade += 10.0 ) {
            double c_to_f = Celsius_to_Fahrenheit( centigrade );   // convert it
            double f_to_c = Fahrenheit_to_Celsius( c_to_f );       // and back again
            cout << centigrade << " " << c_to_f << " " << f_to_c << endl;
        }
    }
    
    // definitions of Celsius() & Fahrenheit()
    
    double Fahrenheit_to_Celsius( double f )
    {
        double result = f - 32;
        result = result * 5.0;
        result = result / 9.0;
        return result;
    }
    
    double Celsius_to_Fahrenheit( double c )
    {
        double result = c * 9.0;
        result = result / 5.0;
        result = result + 32;
        return result;
    }
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.

  6. #6
    Registered User o0o's Avatar
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    thanku salem

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