Hi
I am trying to get the code below displayed as X values where true, and O where false... so for the character array below, im trying to get it to output
X X X
X X O
I have tried a few things such as a for loop (which i think is used?) but it ends up outputting something stupid
Code:char Board[3][3] = { {true,true,true}, {true,true,false},};
Let's see em and we'll go from there.I have tried a few things...
gg
Think about the data type of 'true' and 'false'.
The word rap as it applies to music is the result of a peculiar phonological rule which has stripped the word of its initial voiceless velar stop.
Thats the closest ive got but i dont think its close to being correct as it just displays:Code:for (int q = 0; q < 2; q++) { for (int p = 0; p < 3; p++) { if (Board[q][p] = true) { Board[q][p] = 'X'; cout << Board[q][p]; } if (Board[q][p] = false) { Board[q][p] = 'O'; cout << Board[q][p]; } } cout << endl; }
XXX
XXX
when im trying to get
XXX
XXO (As the bottom right is false)
The char type cannot hold true and false values, learn more about data types.
Do not make direct eye contact with me.
First problem:
if (Board[q][p] = true)
should be:
if (Board[q][p] == true)
>> for (int q = 0; q < 2; q++)
should be:
>> for (int q = 0; q < 3; q++)
Finally, you could save yourself all of those steps by simply doing:
Code:#define SET 'X' #define UNSET 'O' char Board[3][3] = { {SET, SET, SET}, {SET, SET, SET}, {SET, SET, UNSET} };
Code:#include <cmath> #include <complex> bool euler_flip(bool value) { return std::pow ( std::complex<float>(std::exp(1.0)), std::complex<float>(0, 1) * std::complex<float>(std::atan(1.0) *(1 << (value + 2))) ).real() < 0; }
For good programming practice, that really ought to be:
const char SET = 'X';
const char UNSET = 'O';
The word rap as it applies to music is the result of a peculiar phonological rule which has stripped the word of its initial voiceless velar stop.
thanks alot
sorted
